IIT-JEE Admissions 2020-21

IIT-JEE Admissions 2020-21

JEE Main 2019: Know how much is needed to qualify for JEE Advanced

PUBLISH DATE 26th April 2019

JEE Main 2019: All those who clear the Joint Entrance Examination Main are not eligible to appear for JEE Advanced. JEE Main and JEE Advanced have different eligibility criteria; not all who qualify JEE Mains make the cut for Advanced.


JEE Main 2019: The National Testing Agency (NTA) will declare the result for Joint Entrance Examination (JEE) Main 2019 by April 30 at its official website, jeemain.nic.in. The JEE Main is the qualifying exam for JEE Advanced which is the entrance exam for admission to the Indian Institute of Technology (IITs). But not everyone who clears the JEE Main is eligible for JEE Advanced.

The JEE Main which concluded on April 12 is an entrance exam for admissions to both engineering and architecture related undergraduate courses. The JEE Main score is accepted by the private and government colleges alike. So all those who clear the JEE Main are eligible to admission to the UG courses. For each college, there is a different cut-off.

For JEE Advanced, only the candidates who secure a rank in top 2,45,000 are eligible to appear for the exam, according to official notification. The ranks scored in JEE Main 2019 will be announced along with JEE Main 2019 result by the NTA. Thereafter, based on the score secured in JEE Advanced, candidates are given admission to IIT and those who do not qualify can apply.

The percentages of various categories of candidates to be shortlisted are: 4% for EWS category, 27% for OBC-NCL, 15% for SC, 7.5% for ST and the remaining 46.5% is open for all. Within each of these four categories, 5% horizontal reservation is available for PwD candidates, as per the official notification by the IIT Roorkee.

jee main, jee main 2019, jee advanced, je adbanced 2019, jee advance eligibility, jee advance bersus main, jee advance cut off, jee main reuslt 2019, nta, nta result, jeemain.nic.in, jeeadv.ac.in, jee main cut off, engineering entrance exam, iit, iit admission, iit roorkee, education news

JEE Advanced 2019: Eligibility

Also, to be eligible for the exam, candidates should match the eligibility criteria

Number of attempts: A candidate should have appeared for the class 12 (or equivalent) exam for the first time in either 2018 or 2019. No candidate is allowed to take the exam for more than two consecutive years.

Age limit: Candidates should have been born on before October 1, 1994. Further relaxation of five years is allowed for SC, ST, PwD candidates.

The JEE Advanced will be conducted by the IIT-Roorkee in two papers. The paper -1 will begin at 9 am to be concluded at noon and paper 2 will be held from 2 pm to 5 pm.

JEE Advanced 2019: Who are considered foreign nationals?

Candidates who are not citizens of India (by birth or naturalized), do not belong to OCI/PIO category, and whose parents are not citizens of India and do not come under OCI/PIO category at the time of registering for JEE (Advanced) 2019 are treated as foreign nationals, as per the official notice.

Online Mock Exam: NEET JEE MHT CET 2019

Click to View| Upcoming Entrance Exams

India's Leading Educational Web Portal now available on Google play store                 https://goo.gl/HbsLr2
Check FYJC & ALL COURSES UNDER DTE & DMER - Previous & Current Year Cutoff |  http://vidyarthimitra.org/rank_predictor


Download App Now : Cut-offs 2019


Also Read : List Of Foreign Medical Institutions/Universities For MBBS

For all latest Govt Jobs 2019Railway JobsBank Jobs and SSC Jobs log on to https://goo.gl/YPjt94 We bring you fastest and relevant notifications on Bank, Railways and Govt Jobs. Stay Connected